(m+1)x^2+4x+2m=0

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Solution for (m+1)x^2+4x+2m=0 equation:


Simplifying
(m + 1) * x2 + 4x + 2m = 0

Reorder the terms:
(1 + m) * x2 + 4x + 2m = 0

Reorder the terms for easier multiplication:
x2(1 + m) + 4x + 2m = 0
(1 * x2 + m * x2) + 4x + 2m = 0

Reorder the terms:
(mx2 + 1x2) + 4x + 2m = 0
(mx2 + 1x2) + 4x + 2m = 0

Reorder the terms:
2m + mx2 + 4x + 1x2 = 0

Solving
2m + mx2 + 4x + 1x2 = 0

Solving for variable 'm'.

Move all terms containing m to the left, all other terms to the right.

Add '-4x' to each side of the equation.
2m + mx2 + 4x + -4x + 1x2 = 0 + -4x

Combine like terms: 4x + -4x = 0
2m + mx2 + 0 + 1x2 = 0 + -4x
2m + mx2 + 1x2 = 0 + -4x
Remove the zero:
2m + mx2 + 1x2 = -4x

Add '-1x2' to each side of the equation.
2m + mx2 + 1x2 + -1x2 = -4x + -1x2

Combine like terms: 1x2 + -1x2 = 0
2m + mx2 + 0 = -4x + -1x2
2m + mx2 = -4x + -1x2

Reorder the terms:
2m + mx2 + 4x + x2 = -4x + 4x + -1x2 + x2

Combine like terms: -4x + 4x = 0
2m + mx2 + 4x + x2 = 0 + -1x2 + x2
2m + mx2 + 4x + x2 = -1x2 + x2

Combine like terms: -1x2 + x2 = 0
2m + mx2 + 4x + x2 = 0

The solution to this equation could not be determined.

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